Experiment 1 : analyzing the composition of soil by sedimentation method
(A) First beaker
Type of Soil | Length of layer/ cm |
Humus | 0.2 |
Suspension of fine clay | 12.7 |
Clay | 3.5 |
Silt | 0.5 |
Fine sands | 2.4 |
Gravel and coarse | 0.2 |
(B) second beaker
Type of Soil | Length of layer |
Humus | 0.2 |
Suspension of fine clay | 11.4 |
Clay | 0.5 |
Silt | 3.0 |
Fine sands | 2.5 |
Gravel and coarse | 4.0 |
Experiment 7 : To check humidity and temperature
temperature: dry bulb, 1st attemp= 27, 2nd attempt=27, 3rd attempt=26.5... so average 27
temperature: wet bulb, 1st attempt=26.5, 2nd attempt= 25.5, 3rd attempt= 25.5.. average 26
humidity : range between 12.29 to 12.31
RESULT FOR EXPERIMENT 2
Refer to handout for the procedure:
REAGENTS ADDED | OBSERVATION | INTERPRETATION |
BaCl solution | No changes | Sulphates is not present |
Cold FeSO4 solution followed by a few drops of conc. H2SO4 | Dark brown ring formed | Nitrates present |
Dilute HNO3 and ammonium molybdate solution solution | Bringht yellow precipitate formed | Phosphates present |
Silver nitrate solution | No changes | Chlorides not present |
Pg 46, Determining water content of a soil sample
Soil placed in crucible A is obtained from the highest level of the area
Soil placed in crucible B is obtained from the moderate level of the area
Soil placed in crucible C is obtained from the lowest area of the area
Soil sample | Initial mass(crucible+soil)/g | Mass after 24 hours(crucible+soil)/g |
A | 67.80 | 58.94 |
B | 69.60 | 62.15 |
C | 65.05 | 56.39 |
Initial mass of crucible A= 57.80g
Initial mass of crucible B= 59.60g
Initial mass of crucible C=55.05g
Initial mass of all soil sample are 10g
RESULT FOR EXPERIMENT 5
SOIL SAMPLE ARE TAKEN FROM VARIOUS PLACES IN THE RESEARCH AREA.
SOIL SAMPLE | pH |
SOIL A | 5 |
SOIL B | 5 |
SOIL C | 5 |
From shivabarath
Plant species | Abundance on the forest level | ||
Emergent | Medium Layer | | |
A | - | 1 | 4 |
B | - | - | 21 |
C | - | - | 5 |
D | - | 2 | 6 |
E | - | - | 3 |
F | - | - | 29 |
G | 6 | 13 | 18 |
H | 8 | 9 | 12 |
I | 7 | 10 | 17 |
J | - | 14 | 21 |
K | 2 | 10 | 13 |
TABLE. SPECIES DIVERSITY AT THE AREA OF RESEARCH
QUADRAT SPECIES | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
W | 3 | - | 1 | 2 | 4 | 3 | 3 | - | 1 | - |
X | - | - | 1 | 1 | 3 | 2 | 1 | - | 2 | - |
Y | 6 | 3 | 1 | - | 3 | - | - | - | 1 | 3 |
Z | 1 | 2 | 2 | 3 | 1 | - | 3 | 2 | - | 1 |
TABLE. TABLE OF QUADRAT NUMBER
* NAMING OF THE SPECIES IS NOT NECESSARY AS IT IS POSSIBLE TO NAME THEM WITH A, B, C, AND SO ON…
*FROM HERE IT IS DIFFICULT IF WE WANT TO CALCULATE THE SPECIES COVER. SO MY SUGGESTION IS U GUYS CALCULATE ONLY THE SPECIES DIVERSITY (USING ABUNDANCE TABLE, WE ARE NOT USING QUADRAT FOR THIS BECAUSE FOREST CONSIST OF LARGE TREES WHICH WILL BE DIFFICULT TO RELY ON QUADRAT), SPECIES FREQUENCY AND SPECIES DENSITY (USING QUADRAT TABLE). U ALSO WILL BE EXPECTED TO CALCULATE RELATIVE DENSITY AND RELATIVE FREQUENCY. U ALSO WILL BE EXPECTED TO EXPLAIN WHY IT IS HARD TO CALCULATE THE SPECIES COVER IN THE AREA THAT WE CHOOSE. OK.
*DO NOT FORGET TO INCLUDE A FEW PICTURES IN THE REPORT TO SHOW THAT IT IS A HIGH ABUNDANCE SPECIES AREA.
* IN YOUR REPORT IT IS UP TO YOU ON HOW TO ORGANISE
Option 1.
Procedure (a): …………………………
Result (a): ……………………………..
Discussion (a) : ………………………
Procedure (b): …………………………….
Result (b): ……………………………….
Discussion (b) : ……………………………
Procedure (c): …………………………….
Result (c): ……………………………….
Discussion (c) : ……………………………
Or
Option 2
Procedure (a): ………………………………
Procedure (b): …………………………
Procedure (c): ………………………………..
Result (a): ……………………………….
Result (b): ……………………………….
Result (c): ……………………………….
Discussion (a) : ……………………………
Discussion (b) : ……………………………
Discussion (c) : …………………………… from: momo chihuahua
thanks syed :)
ReplyDeleteok welcome.... read all again...
ReplyDeletethx a lot syed
ReplyDelete