I only demonstrate for snail 1… so u guys should try for snail 2…
Snails | Number of times the snail has been stimulated | Rank stimulation | Time/s | Rank time | Different/D | D² |
Snail 1 | 1 | 10 | 77.3 | 1 | 9 | 81 |
2 | 9 | 38.8 | 2 | 7 | 49 | |
3 | 8 | 26.6 | 3 | 5 | 25 | |
4 | 7 | 19.7 | 4 | 3 | 9 | |
5 | 6 | 15.1 | 5 | 1 | 1 | |
6 | 5 | 7.7 | 6 | -1 | 1 | |
7 | 4 | 5.3 | 7 | -3 | 9 | |
8 | 3 | 3.1 | 8 | -5 | 25 | |
9 | 2 | 0 | 9.5 | -7.5 | 56.25 | |
10 | 1 | 0 | 9.5 | -8.5 | 72.25 |
This is the table that u need to draw for the purpose of statistical calculation.
1. rank the stimulation with the highest number being number one. (column 3)
2. rank time with the highest time being number one. (column 5)
3. If 2 data in the column appear to be the same, (for eg, for 9^{th} and 10^{th} stimulation, time both equal to zero,) find the mean value… so… 9 + 10 / 2 = 9.5…. so 9.5 is rank for both….
4. Then find the difference between the rank. (Column 6)
5. Then squared the rank. (last column)
6. Then calculate the ΣD²
7. then use this formula
rs = 1- 6 ΣD²/n(n²-1)
Where n= number pair of data, which is in our case 10.
8. Compare the value u get with critical value… ok… REMEMBER TO CALCULATE FOR SNAIL 2 TOO…
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